Math 125 Exam 2 Practice
Earl M. Rodd - Fall 2008
The exam will have problems of these types:
- Review:
Identify a number which is irrational in a list of numbers.
Identify a number which is an Integer in a list of numbers.
Identify an invalid use of basic principles.
- Complete several sequences and identify whether the sequence is
arithmetic or geometric. For example:
Find the next two terms: -5, -1, 3, 7, Answer is: 11,15
because each term is 4 bigger. This is an arithmetic sequence.
Find the next two terms: -1, 3, -9, 27, Answer is -81, 243
because each term is (-3) times the previous one. This is
a geometric sequence.
- Solve equations. For example.
20 - x = 100
-x = 80
x = -80
x/10 = x-3
x = 10(x-3)
x = 10x - 30
x - 10x = -30
-9x = -30
9x = 30
x = 30/9 = 10/3
- Watch out for
equations like these:
5(x + 10) = 50 + 5x
5x + 50 = 50 + 5x
0 = 0 Solution: All reals
5(x + 10) = 40 + 5x
5x + 10 = 40 + 5x
10 = 40 NO. Solution: Null (no solution)
Note: There are 4 equations to solve early in the exam and 4 more
at the end.
There are equations with a simple fraction (e.g. x/5 + 2 = 4),
one with decimals and several which require the use of the distributive
principle (e.g. 2(x + 3) = 4 - 2x)
-
Compute values of these formulas:
If b = 2 and h = 10, and A = 1/2 bh, compute A.
A = 1/2 x 2 x 10 = 10
If w = 5 and L = 20 and P = 2w + 2L, compute P
P = 2x5 + 2x20 = 50
If x = -20, |10+x| = |10 - 20| = |-10| = 10
- Solve the formulas.
Solve A = 1/2 bh for h
2A = bh
h = 2A/b
Solve P = a + b + c for c
P - a - b = c
- Geometry problems like the two below.
- The perimeter of a triangle is 49. One side is two times the first and
the other side is 1/2 the first. What are the sides?
a = first side
2a = second
a/2 = third
a + 2a + a/2 = 49 (clear fractions first by multiplying by 2)
2a + 4a + a = 98
7a = 100
a = 14
2a = 28
a/2 = 7
- In a triangle, the one angle is twice the first and the third is
three times the first. What are the angles?
x = first angle
2x = second angle
3x = third angle
x + 2x + 3x = 180 (sum of angles of a triangle is 180)
6x = 180
x = 30
First angle=30
Second angle = 60
Third angle = 90
- Percentage problems like the two below.
- If the tax rate is 9%, what is the tax on a $40.00 meal?
(Warning: This is simple to do on a calculator, but you MUST write
the correct equation to get credit!)
Tax = rate x amount
t = .09 * 40.00
t = 3.60
- The price of gasoline went up 15% since last week. The new price is
$3.45. What was the old price?
p = old price
p + .15*p = 3.45 (original price + 15% of original price)
1.15p = 3.45
p = 3.00
- In the following solution to an equation, write the principle used
to justify the step by the step.
4(4 - x) + 5 = 6x - 3
16 - 4x + 5 = 6x - 3 DISTRIBUTIVE
16 + 5 - 4x = 6x - 3 COMMUTATIVE - changed order
21 - 4x = 6x - 3
-4x = 6x- 24 EQUALITY PRINCIPLE
(add -21 to both sides)
-10x = -24 EQUALITY PRINCIPLE
(add -6x to both sides)
x = 24/10 = 12/5 EQUALITY PRINCIPLE
(divide both sides by -10)
(i.e. multiple both sides by -1/10)